- Thread starter Sarmmer
- Start date

However, I have a situation where there are 3 types of outcomes (eg. win, lose and tie).

Please share your thoughts if it shall be done in other ways. Thank you.

P, p, q, r = probability

n = number of ways event can occurs

x, y, z = targeted outcome

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- Nov 12, 2017

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This is not very clearly stated; but the formula at the top is for theHi everyone, this is my first thread here.

Would need your experience and comments on the following:

View attachment 26412

where

p + q + r = 100%

x + y + z = n

The formula at the bottom does give the probability of x wins, y losses, and z ties out of n trials with respective probabilities p, q, r.

This is still not stated quite right, though it is better. n is not the number of ways an event can occur, but the number of trials. x, y, and z are the number of each of the three outcomes in those n trials.

However, I have a situation where there are 3 types of outcomes (eg. win, lose and tie).

Please share your thoughts if it shall be done in other ways. Thank you.

P, p, q, r = probability

n = number of ways event can occurs

x, y, z = targeted outcome

See https://en.wikipedia.org/wiki/Multinomial_distribution