aem2177 said:

I have no clue how to factor, which seems to be a big chunk of what's going to be on my exam.

I have one problem done that I THINK I did right, but I'm not sure.

y(b+9)+5(b+9)

=(y+5)(b+9)

I don't know if that's right or not, but I remember my teacher saying something like "factor by grouping" and it looking similar to that.

I have a number of other problems from the study guide that I simply do not even know where to begin with. I'll list two.

1. z^2+7zy+5z+35y

2. 7x^2-70x+147

Any help on the steps to do these would be greatly appreciated!

Hi aem2177,

You did fine with your grouping. Good job.

1. \(\displaystyle z^2+7zy+5z+35y\)

This one's already grouped. Factor

**z** from the first group, and then factor

**5 **from the second group.

\(\displaystyle z(z+7y)+5(z+7y)\)

Now, finish up like you did the last one.

2. \(\displaystyle 7x^2-70x+147\)

Now, 7 is a factor of all three terms, so if we factor that out first, we have,

\(\displaystyle 7(x^2-10x+21)\)

Now, I think you can factor the trinomial in parentheses, can't you?