fiskonian said:I need help with this problem.
1/9(x+18)+1/3(2x+3)=x+3
I know the answer is 0 because i looked in the back of the book to check my work.
However i cannot seem to work it out to get 0. please help me.
Working backwards from the answer, I think you mean:fiskonian said:I need help with this problem.
1/9(x+18)+1/3(2x+3)=x+3
Hint: 9(x) does not equal x. :wink:fiskonian said:1/9(x+18)+1/3(2x+3)=x+3
9(1/9[x+18]+1/3[2x+3]=x+3)
x+18+6x+9=x+27
fiskonian said:ok.
1/9(x+18)+1/3(2x+3)=x+3
9(1/9[x+18]+1/3[2x+3]=x+3)
x+18+6x+9=x+27
7x+27=x+27 (once i got to here i knew the answer... finding out how to get to there was what i had problems with.)
6x=0
x=0
im not sure if this is followable, its hard to show my work on this. PS- ill probably be on here alot these next few years