H Hails13 New member Joined Mar 3, 2010 Messages 1 Mar 3, 2010 #1 Each of the two smaller angles of a parallelogram measures 18 degrees less than each of the two larger angles. Find the measure of the four angles. How would you set this up?
Each of the two smaller angles of a parallelogram measures 18 degrees less than each of the two larger angles. Find the measure of the four angles. How would you set this up?
B BigGlenntheHeavy Senior Member Joined Mar 8, 2009 Messages 1,577 Mar 3, 2010 #2 \(\displaystyle (x-18)+(x-18)+x+x \ = \ 360\)
S soroban Elite Member Joined Jan 28, 2005 Messages 5,584 Mar 3, 2010 #3 Hello, Hails13! Did you make a sketch? Each of the two smaller angles of a parallelogram is 18 degrees less than the two larger angles. Find the measure of the four angles. Click to expand... Code: * - - - - - - - - * / / / / / / / / / x-18 x / * - - - - - - - - * Two adjacent angles of a parallelogram are supplementary. So we have: .\(\displaystyle (x-18) + x \:=\:180^o\)
Hello, Hails13! Did you make a sketch? Each of the two smaller angles of a parallelogram is 18 degrees less than the two larger angles. Find the measure of the four angles. Click to expand... Code: * - - - - - - - - * / / / / / / / / / x-18 x / * - - - - - - - - * Two adjacent angles of a parallelogram are supplementary. So we have: .\(\displaystyle (x-18) + x \:=\:180^o\)
