need help with inequalities: 2(3x - 16) < -3(x + 16)

mathisnotfun

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Jan 10, 2008
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I have a homework problem that is troubling me.

2(3x-16)<-3(x+16)

I have no clue how to do this at all. thanks for helping
 
Re: I need help please

mathisnotfun said:
I have a homework problem that is troubling me. 2(3x-16)<-3(x+16). I have no clue how to do this at all. thanks for helping

"no clue" is not a good thing!

Solving an inequality involves basically the same process as solving an equation.

You have

2(3x - 16) < -3(x + 16)

Let's start by doing the multiplications on both sides so that we can get rid of the parentheses:

2*3x - 2*16 < -3*x + (-3)*16

6x - 32 < -3x - 48


*
Now, let's get rid of the variable term from one side of the inequality. Though it really doesn't matter which side you eliminate the variable from, in my experience, it is easiest to get rid of the smaller variable term.

The smallest variable term is -3x. To eliminate this term, add +3x to both sides of the inequality:

6x - 32 + (3x) < (-3x) - 48 + 3x

9x - 32 < -48

Now, you want the term containing the variable to be by itself. Add 32 to both sides of the equation:

9x - 32 + 32 < -48 + 32
9x < -16

Finally, to get just y on one side, divide both sides by 9:

(9x)/9 < (-16)/9

x < (-16/9)


Now, the checking is up to you.
 
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