Check where you put that constant! But if it's not a typo, I'd interpret it differently.∫x dyx = (∫x dy)x? = (xy)x+c = x2y + c
If it was indeed \(\displaystyle \left(\int x dy\right)x\) and x and y are independent variables then the integral is \(\displaystyle (xy+ c)x= x^2y+ cx\).∫x dyx = (∫x dy)x? = (xy)x+c = x2y + c
+cx, thanks for the catch!Check where you put that constant! But if it's not a typo, I'd interpret it differently.