It seems that there is some information missing. If \(\displaystyle \omega\) is a (complex) cube root of -1 then we know that \(\displaystyle \omega ^2 + \omega + 1 = 0\).
-Dan
My main point here is that you didn't supply the whole problem...Please check the attachment below, the rectangle
I was doing some research on google and I cam across same info that ω2+ω+1=0 so ω2+ω=-1. I think this proves it. ( I think the problem arose as We have not started cube root of Unity)
My main point here is that you didn't supply the whole problem...
-Dan