Need Help with some questions

sunny123

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Jul 28, 2019
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Hi I need help in solving the following equation. This question is Picked up from subject BCS12 Page 6. I have solved it on paper but I am not able to understand some logic. Please see the paper for further details.

13059
 

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It seems that there is some information missing. If \(\displaystyle \omega\) is a (complex) cube root of -1 then we know that \(\displaystyle \omega ^2 + \omega + 1 = 0\).

-Dan
 
Please check the attachment below, the rectangle
It seems that there is some information missing. If \(\displaystyle \omega\) is a (complex) cube root of -1 then we know that \(\displaystyle \omega ^2 + \omega + 1 = 0\).

-Dan

I was doing some research on google and I cam across same info that ω2+ω+1=0 so ω2+ω=-1. I think this proves it. ( I think the problem arose as We have not started cube root of Unity)
 
Please check the attachment below, the rectangle


I was doing some research on google and I cam across same info that ω2+ω+1=0 so ω2+ω=-1. I think this proves it. ( I think the problem arose as We have not started cube root of Unity)
My main point here is that you didn't supply the whole problem...

-Dan
 
My main point here is that you didn't supply the whole problem...

-Dan

Dan can you please explain, since my book gave me a question in the same manner. Like I have posted in first image. I was able to solve all of them except question (d) ( Which I was only able to solve partially) After you mentioned unity I googled it and found the reason for the answer. My main stream is not math, So this is new to me.

13063
 
Thank you. I see no reason why the solution manual (or instructor?) should have stated that \(\displaystyle \omega\) should be considered to be a cube root of -1. It is standard notation (sort of) but I see no reason why you would have applied it to this problem.

-Dan
 
At some point previously in the book, there must have been the statement that \(\displaystyle \omega\) would represent the principle cube root of -1.
 
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