Need help with these problems PLEASE!! THANK YOU

[koreanstar88]

1) (Squareroot 5 - Squareroot 6)^2


Is expanding this squared binomial (?) a good idea??


2) Also for this type of problem ...

Square root 128c^2d^4


am i supposed to do something to the inside before i put the whole thing to the 1/2 power. i tried just putting the whole thing to the 1/2 power and i have alot of trouble simplifying it for some reason...

same goes with the 1/3, 1/4 power type of problems..


Please advise thank you

 

[Mrspi]

1) (Squareroot 5 - Squareroot 6)^2


Is expanding this squared binomial (?) a good idea??


2) Also for this type of problem ...

Square root 128c^2d^4


am i supposed to do something to the inside before i put the whole thing to the 1/2 power. i tried just putting the whole thing to the 1/2 power and i have alot of trouble simplifying it for some reason...

same goes with the 1/3, 1/4 power type of problems..


Please advise thank you

For your first problem YES...expand the binomial.

For the second problem, I'd write (128c^2d^4)^(1/2)( this way:

[2^7 c^2 d^4)^(1/2)

Now....can you take it from here?

 

[Denis]

2) Also for this type of problem ...
Square root 128c^2d^4
am i supposed to do something to the inside before i put the whole thing to the 1/2 power. i tried just putting the whole thing to the 1/2 power and i have alot of trouble simplifying it for some reason...

What are you asking exactly?
sqrt(128c^2d^4) is simply another way to show (128c^2d^4)^(1/2)

sqrt(128c^2d^4)
= sqrt(64 * 2 * c^2 * d^4)
= 8cd^2 sqrt(2)

 

[koreanstar88]

1) (Squareroot 5 - Squareroot 6)^2


Is expanding this squared binomial (?) a good idea??


2) Also for this type of problem ...

Square root 128c^2d^4


am i supposed to do something to the inside before i put the whole thing to the 1/2 power. i tried just putting the whole thing to the 1/2 power and i have alot of trouble simplifying it for some reason...

same goes with the 1/3, 1/4 power type of problems..


Please advise thank you

For your first problem YES...expand the binomial.

For the second problem, I'd write (128c^2d^4)^(1/2)( this way:

[2^7 c^2 d^4)^(1/2)

Now....can you take it from here?

How would I take the 2^7 to the 1/2 power?
I don't understand how that would help instead of leaving it as 128..?

 

[Deleted member 4993]

How would I take the 2^7 to the 1/2 power?

(2^7)^(1/2) = 2^(7/2) = 2^3 * 2^(1/2) = 8 * 2^(1/2)


I don't understand how that would help instead of leaving it as 128..?