- Thread starter FrontS
- Start date

- Joined
- Aug 27, 2012

- Messages
- 311

Interesting idea. How did you come up with this?Hello, and welcome to FMH!

Hint: Try arranging the quartic expression in \(m\) as a quadratic in \(m^2+2m\).

-Dan

- Joined
- Nov 24, 2012

- Messages
- 1,292

I put the expression "(m-1)(m-2)(m+3)(m+4) " into W|A to see what I got, and one form it gave was a quadratic in \(m^2+2m\). This makes answering the question straightforward, and without having to know the value of \(m\), which for problems like this, I think is a general desire by the authors of these problems.Interesting idea. How did you come up with this?

-Dan