Narwalalpaca12$
Junior Member
 Joined
 Sep 15, 2019
 Messages
 50
Need help with this. Problems one and 4.
Attachments

282.2 KB Views: 18
Could you give me an example please?Both of the problems you ask about have a variable in the denominator. A key step will be to multiply both sides by the denominator, in part to get the variable out of there. There's more to do here than just eliminate a coefficient.
But you are also doing things that don't accomplish what you claim. Does \(\displaystyle \frac{4}{3k}\cdot\frac{4}{3} = k\) as you claim? Write it out this way, rather than in a column, and think carefully about it.
Example of what?Could you give me an example please?
I just don’t understand what he’s sayingExample of what?
Have you studied fraction multiplication and division?
Let's take an easy example. 4=8/x. First, can you figure out what x is without 'solving' the equation?I just don’t understand what he’s saying
Ok.
Bu that’s not the answerSo would I do this...
1. 4*k= (3/k)*k = 4K/3k=8
2.4k/3k divided by 4/3 is k/k and 8 divided by 4/3 = 6
Rule number 1: never forget about signs! A huge number of errors in algebra are caused by incorrect handling of signs.So would I do this...
1. 4*k= (3/k)*k = 4K/3k=8
2.4k/3k divided by 4/3 is k/k and 8 divided by 4/3 = 6
About which part?I am very confused
Which step? Did you understand the 4=8/x example?The steps
I didn’t understand what you did with the first step