Need help

New member
Both of the problems you ask about have a variable in the denominator. A key step will be to multiply both sides by the denominator, in part to get the variable out of there. There's more to do here than just eliminate a coefficient.

But you are also doing things that don't accomplish what you claim. Does $$\displaystyle \frac{-4}{3k}\cdot-\frac{4}{3} = k$$ as you claim? Write it out this way, rather than in a column, and think carefully about it.
Could you give me an example please?

lev888

Full Member
Could you give me an example please?
Example of what?
Have you studied fraction multiplication and division?

New member
Example of what?
Have you studied fraction multiplication and division?
I just don’t understand what he’s saying

lev888

Full Member
I just don’t understand what he’s saying
Let's take an easy example. 4=8/x. First, can you figure out what x is without 'solving' the equation?

New member
So would I do this...
1. 4*k= (3/k)*k = 4K/3k=8
2.4k/3k divided by 4/3 is k/k and 8 divided by 4/3 = 6

New member
I am very confused

lev888

New member
I didn’t understand what you did with the first step

Dr.Peterson

Elite Member
Let's look at $$\displaystyle 4 = \frac{8}{x}$$.

We want to solve for x; but it is in the bottom of a fraction, which is not good. In order to undo that division by x, we multiply both sides by x. Since the right side is a fraction, it will be helpful to write x as the fraction x/1:

$$\displaystyle 4\cdot x = \frac{8}{x}\cdot\frac{x}{1}$$​

When we do that multiplication, the x cancels out:

$$\displaystyle 4x = \frac{8}{1}$$​

So we have $$\displaystyle 4x = 8$$.

Now, we want to get x by itself, so we have to undo the multiplication by 4; we do that by dividing by 4:

$$\displaystyle \frac{4x}{4} = \frac{8}{4}$$​

$$\displaystyle x = 2$$​

If you don't follow that, please tell us, again, where you are having trouble, and why.