First, the derivative of f+ g is the derivative of f plus the derivative of g and the derivtive of a constant, 45, is 0 so this is the same as the derivative of just −45e−2ln(90)x
Second, the derivative of a constant, -45, times f is that constant times the derivative of f so that is -45 times the derivative of e−2ln(90)x.
Third the derivative of e to the f power is e to the f power times the derivative of f so we have −45e−2ln(90x) times the derivative of 2ln(90)x=(2ln(90))x.
And that, again, is a constant times x so its derivative is just −2ln(90).
So the derivative of −45e−2ln(90)x+45 is (−45)(−2ln(90))e−2ln(90)x
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