defeated_soldier
Junior Member
- Joined
- Apr 15, 2006
- Messages
- 130
The following simple facts should be remembered:
1) An ordinary year contains 365 days; that is, 52 weeks and 1 odd day.
2) A leap year contains 366 days; that is, 52 weeks and 2 odd days.
3) One hundred years (a century) contain 76 ordinary years and 24 leap years:
. . .= (76 × 52) weeks + 76 odd days + (24 × 52) weeks + 48 odd days
. . .= [(76 × 52) + (24 × 52)] weeks + 124 odd days
. . .= [(76 × 52) + (24 × 52) + 17] weeks + 5 odd days
That is, 100 years contain 5 odd days.
Two hundred years contain 10 and thus 3 odd days. Similarly, 300 years contain 1 odd day, and 400 years will have (20 + 1) odd days; that is, 0 odd days. Similarly, the years 800, 1200, 1600, and 2000 each contains no odd days.
4) First January 1 AD was Monday. Therefore, we must count days from Sunday; that is, Sunday for 0 odd days, Monday for 1 odd day, Tuesday for 2 odd days, and so on.
5) February in an ordinary year gives no odd day, but in a leap year gives one odd day.
QUESTION 1: (Regarding the above...)
I dont understand the phrase "400 years will have (20+1) odd days i.e 0 odd days"
This is confusing. We have seen 100 years contains 5 odd days, so naturally 400 years will contain 5 x 4 = 20 odd days. I don't understand why they are saying "20+1 odd days"? Where is this extra "1" coming from?
I think the extra 1 may be due to 400 years being a leap year. However, as we have already considered leap year in 100 years, there is no meaning to count it again for 400 years being a leap year -- is there? I'm feeling like my logic must be wrong.
QUESTION 2: On what of the week did the 17th of November, 1982 fall?
I started this way:
1982=100 x 19+ 82 =5 odd days x 19 + 82 years
17th november = 11 month + 17 days
I don't know whether I am on the right track, and the calculation is becoming complex. Is this even the right way to go?
Thank you!