- Thread starter mr.burger
- Start date

The x intercept is at

-3/4*x+9/4+4 = 0

3x=25

x=25/3

Assuming the normal is to the x axis the triangle is P(3,4), P(3,0) and P(25/3,0)

The area is .5*4*(25/3-3) = 32/3

That will give you a check if you feel it should be an integral.

y-4 = (-3/4)(x-3)

The x intercept of the tangent (y=0) is the second point of the triangle. If the normal is to the x axis then it starts at the third point P(3,0) and goes up to P(3,4)

We are in the first quadrent so sketching a quarter of a circle and marking those three points shouldn't be too hard. If you don't have graph paper you can print some from

http://www.mathematicshelpcentral.com/graph_paper.htm

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Here we have an example that you may need to back up, leave calculus alone for a while, and brush up on your analytic geometry. There are reasons why course listings include prerequisites.mr.burger said: