- Thread starter jazz2112
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What are the intercept and slope for the line you identified, v =

Then go back and fix that equation, too! It is not quite true that log(5^{t/2}) = t log(5/2). Do you see where the 2 should really be? Then you can answer the question using the correct line.

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log(a

We see on the left-hand side (above) that n is the exponent.

log(5

That is, the base is 5 and the exponent is t/2.

In the symbolic expression log(a

Therefore, what is n∙log(a) ?

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Yes. In the form:Or is the slope ... log(5)/2 ...

y = m∙x + b

we see that slope m is the Real number multiplying independent variable x.

In the form:

V = log(5)/2∙t + log(3.8)

we see that expression log(5)/2 is the Real number multiplying independent variable t.

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That looks more like it ...Or is the slope just equal to log(5)/2 which would be equal to 0.35?