This question is for my 10 year old (Year 6 in the UK).

**[FONT="]A bird has 2 legs, a cat has 4 legs, an insect has 6 legs and a spider has 8 legs.[/FONT]**

[FONT="]Claire looks at some animals and counts all their legs.[/FONT]

[FONT="]She counts 38 legs.[/FONT]

[FONT="]There are twice as many birds as spiders and twice as many cats as insects.[/FONT]

[FONT="]

[FONT="]Claire looks at some animals and counts all their legs.[/FONT]

[FONT="]She counts 38 legs.[/FONT]

[FONT="]There are twice as many birds as spiders and twice as many cats as insects.[/FONT]

**How many of each type of animal can she see?**

[/FONT]

We tried to build an equation based on the above:

b + c + i + s = 38

but for me this does not sound right because b,c,i and s will need to be total number of animals that make 38 legs?

Then we have the information where there are twice as many birds as spiders and twice as many cats as insects.

So this will make the above equation:

2s + 2i + i + s = 38

3s + 3i = 38

...i do not think i am going anywhere with this...so we tried the "manual" method

bird has two legs

cat has 4 legs

insect has 6 legs

spider has 8 legs

so at the minimum level if we add all the legs to together we get:

birds (4) + cats (8) + Insects (6) + spider (8) = 26

but we still need to get 38 i.e 38 - 26: 12 more...however we cannot see how we can get 12 more because there is a link between cats and insects, birds and spiders...if we add an insect or spider we will only go upto 36....

Any direction on this will be helpful.

saf