#### aron101782

##### New member

- Joined
- Jan 18, 2019

- Messages
- 22

A B C

such that

0<A<2

0<B<2

0<C<1

What is a convenient way to determine the number of combinations in this sequence

- Thread starter aron101782
- Start date

- Joined
- Jan 18, 2019

- Messages
- 22

A B C

such that

0<A<2

0<B<2

0<C<1

What is a convenient way to determine the number of combinations in this sequence

- Joined
- Nov 12, 2017

- Messages
- 4,690

Also, you can't be using the word "combinations" in its technical sense, as clearly order matters.

Can you clarify the question?

- Joined
- Dec 30, 2014

- Messages
- 3,765

Since A is between 0 and 2 there are infinite number of numbers that A can be

A B C

such that

0<A<2

0<B<2

0<C<1

What is a convenient way to determine the number of combinations in this sequence

Since B is between 0 and 2 there are infinite number of numbers that B can be

Since C is between 0 and 1 there are infinite number of numbers that C can be

Continue from here

- Joined
- Jan 18, 2019

- Messages
- 22

0<=A<=2 : 0 1 2

0<=B<=2 : 0 1 2

0<=C<=1 : 0 1

What is a convenient way to determine the number of possibilities for ABC

- Joined
- Nov 12, 2017

- Messages
- 4,690

How many ways are there to choose A?

For each of those, how many ways are there to choose B?

How many ways, therefore, are there to choose a pair A, B?

Now continue.

- Joined
- Jan 29, 2005

- Messages
- 8,527

The terms \(\displaystyle ABC\) count is \(\displaystyle 3\cdot 3\cdot 2=18 \)

0<=A<=2 : 0 1 2

0<=B<=2 : 0 1 2

0<=C<=1 : 0 1

What is a convenient way to determine the number of possibilities for ABC

I not know what more you are asking.

- Joined
- Jan 18, 2019

- Messages
- 22

so there would be 18 combinations for ABC