M math_fan New member Joined Jan 6, 2014 Messages 8 Mar 22, 2014 #1 Given that I can prove \(\displaystyle mn(m+n)(m-n)≡0\ mod\ 6\) I have a further value \(\displaystyle 4k^2 mn(m+n)(m-n)\) Would I be correct in asserting that \(\displaystyle 4k^2 mn(m+n)(m-n)≡0\ mod\ 24k^2\) Thanks
Given that I can prove \(\displaystyle mn(m+n)(m-n)≡0\ mod\ 6\) I have a further value \(\displaystyle 4k^2 mn(m+n)(m-n)\) Would I be correct in asserting that \(\displaystyle 4k^2 mn(m+n)(m-n)≡0\ mod\ 24k^2\) Thanks