Number Theory - square-free integers & tau.

Jamers328

Junior Member
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Sep 20, 2007
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If n is a square-free integer, prove that Tau(n) = 2^r, where r is the number of prime divisors of n.

I know what a square-free integer is... n=p1,p2,...pr. There are no exponents on square-free integers. Anyway, I still have no idea what to do, or where to start with this proof. :(

Also, sorry I did not know how to write the tau symbol on this forum.

Thank you for your help!
 
What does \(\displaystyle \L \tau\(n\)\) represent?
 
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