If n is a square-free integer, prove that Tau(n) = 2^r, where r is the number of prime divisors of n.
I know what a square-free integer is... n=p1,p2,...pr. There are no exponents on square-free integers. Anyway, I still have no idea what to do, or where to start with this proof.
Also, sorry I did not know how to write the tau symbol on this forum.
Thank you for your help!
I know what a square-free integer is... n=p1,p2,...pr. There are no exponents on square-free integers. Anyway, I still have no idea what to do, or where to start with this proof.
Also, sorry I did not know how to write the tau symbol on this forum.
Thank you for your help!