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numbers in progression...
- Thread starter azajewel
- Start date
azajewel said:What is the next number in this progression? 5, 25, 125, 625...
750
1250
3125
390,625
I can't figure out the sequence here, any help is appreciated.
You might want to look at how the GIVEN numbers are related.
Do you see that the first number (5) multiplied by 5, gives the second number?
And that the second number (25) multiplied by 5, gives the third number?
Now....you might want to take this train of thought a bit further.....
BigGlenntheHeavy
Senior Member
- Joined
- Mar 8, 2009
- Messages
- 1,577
\(\displaystyle a_n \ = \ a_1r^{n-1}, \ a_n \ = \ last \ term, \ a_1 \ = \ first \ term, \ n \ = \ number \ of \ terms,\)
\(\displaystyle and \ r \ = \ common \ ratio. \ Can \ you \ take \ it \ from \ here?\)
\(\displaystyle Or \ 5^1,5^2,5^3,5^4,5^?\)
\(\displaystyle and \ r \ = \ common \ ratio. \ Can \ you \ take \ it \ from \ here?\)
\(\displaystyle Or \ 5^1,5^2,5^3,5^4,5^?\)
B
b.morales99
Guest
That is perfectly right. I would also suggest checking out their common denominator next time so you will know the next in line.