Given any finite set of data, there exist an infinite number of possible function that satisfy that data so there is no one "correct" answer to this problem. It is true that given n data points, there exist a unique polynomial of degree n-1 that passes through those data points. Here you are given 5 data points so there exist a unique polynomial of degree 4 giving this data.
Any such polynomial can be written \(\displaystyle y= ax^4+ bx^3+ cx^2+ dx+ e\). Putting (x, y) from your data into that equation gives you five equations to solve for a, b, c, d, and e.
A variation of this same idea is to use "Newton's divided difference formula". A polynomial satisfying this data is \(\displaystyle 42\frac{(x- 180)(x- 160)(x- 140)(x- 122)}{(190- 180)(190- 160)(190- 140)(190- 122)}\)\(\displaystyle + 37\frac{(x- 190)(x- 160)(x- 140)(x- 122)}{(180- 190)(180- 160)(180- 140)(190- 122)}\)\(\displaystyle + 24\frac{(x- 180)(x- 190)(x- 140)(x- 122)}{(160- 190)(160- 180)(160- 140)(160- 122)}\)\(\displaystyle + 16\frac{(x- 190)(x- 180)(x- 160)(x- 122)}{(140- 190)(140- 180)(140- 160)(140- 122)}\)\(\displaystyle + 10\frac{(x- 190)(x- 180)(x- 160)(x- 140)}{(122- 190)(122- 180)(122- 160)(122- 140)}\).