odd, even, neither functions: g(t) = cbrt[t] - 1

[unregistered]

I was determining whether functions were odd, even, or neither and feeling fairly confident about the whole process, substituting x for -x and all, but then I get to this:

In the past I have had to simplify the square but how would I work this the other way around especially with a variable? I just don't even know where to start.

Thanks for any help.

 

[unregistered]

My fault, the equation is actually:

Sorry, thanks.

 

[pka]

\(\displaystyle \L
g(t)\ = \limits^? g( - t)\quad \Rightarrow \quad \sqrt[3]{{t - 1}}\ = \limits^? \sqrt[3]{{ - t - 1}}\)

 

[unregistered]

huh? Can I leave it like that? I thought that a negative radical was invalid or undefined. I'm totally lost. I guess this is neither odd nor even from the look of it but I will try to figure out why. Thanks PKA.

 

[pka]

You are correct it is neither even nor odd.
We can find the cube root (any odd root) of negative numbers.

 

[unregistered]

aaaaah, nice, thanks bro.