Ohms Law problem

[Dancoates]

Hello, sorry if this is the wrong place I cannot find Physics.

I have a problem here and I cannot figure out how to get to the given answer. I can work out the parralel but it is asking for the current through the 20 ohm resistor.

Any advice would be helpful!
See attached.

Thanks
Dan

 

[Deleted member 4993]

Hello, sorry if this is the wrong place I cannot find Physics.

I have a problem here and I cannot figure out how to get to the given answer. I can work out the parralel but it is asking for the current through the 20 ohm resistor.

Any advice would be helpful!
See attached.

Thanks
Dan

Calculate the TOTAL resistance of the circuit first (for which you will need to calculate the equivalent resistances of the parallel parts first).

Please show your work.

 

[Romsek]

Ok so you say you've worked out the circuit to the point that you've got the current flowing into the parallel network of 3 resistors at the right.

Let's just call this \(\displaystyle i\).

You know that this parallel network is equivalent to a single resistor of \(\displaystyle \dfrac{25}{4}\) ohms.
There for the voltage across this network to ground is \(\displaystyle V=\dfrac{25i}{4}\) volts.
This voltage is the same for each resistor in the parallel network.

Therefore the current going through the 20 ohm resistor is \(\displaystyle i_{20} = \dfrac{V}{20} = \dfrac{25i}{80} = \dfrac{5i}{16}\) amps.