I have f(x) = 2x^2 - 8x and g(x) = x+2
find the domain and range of f(g(x)) = 2*(x+2)^2 - 8*(x+2) = 2x^2 - 8
then I thought I could make y = 0 for the domain and then make x = 0 for the range.
0 = 2x^2 - 8
2x^2 = 8
x^2 = 4
x = 2
therefore,
-2 <= x <= 2
then,
y = 2*0^2 - 8
therefore,
y = -8, but now I realize I could plug 2 in to it, but I don't think that's right.