is this the answer or just a guess? why not 21.45873 V\displaystyle 21.45873 \ V21.45873 V
no, it's called sarcasm
while the problem is stated as is, there are five problems layered on top of each other (which i am not gonna reveal)
[math]U=I*R (resistive\ load), U=I*L*\omega(inductive\ load), U=I*\frac{1}{\omega*C}\\units:R(\Omega,ohm),L(H,Henry),C(F,Farad),f(Hz,Hertz),\omega(rad/s)[/math]
understanding the consept of a static vector (ohm law with respect to resistive load:U,R,I can be represented as static vectors on the X-axis)
expanding on the idea: resistive networks (algebra:serie,parallel,compound,2D,3D,....)
understanding the concept of a rotating vector (goniometry:the unit circle,pythagoras,thales,...)
[math]f(x)=sin(x)\\the\;zero's(0): \sum_{n=0}^{\infty}n*\pi\\the\; maxima(+1) : \sum_{n=0}^{\infty}n*\frac{\pi}{2}\\the\;minima(-1):\sum_{n=0}^{\infty}n*\frac{3\pi}{2}[/math]
the basic idea: a vector rotating counterclockwise) around a centerpoint (0,0)
[math]the \;amplitude \; of \;the \;sine : f(x)= a*sin(x),x\in \R\\ the\; phase\; of\; the\; sine : f(x)=sin(x+\alpha),\alpha\; in\;rad\\ the\; frequency\; of\; the\; sine : f(x)=sin(x*n), n\in\N\\[/math]
understanding the consept of a rotating angle (2 rotating vectors locked in phase):
[math]resistor:\alpha=0,\overrightarrow{\rm U}=\overrightarrow{\rm I}\\ capacitor:\alpha= \pi,\overrightarrow{\rm U}+\pi=\overrightarrow{\rm I}\\ inductor:\alpha= \pi, \overrightarrow{\rm U}-\pi=\overrightarrow{\rm I}\\[/math]
understanding a compound power source as: an offset vector (DC component), which displaces the centerpoint of the rotating vector or rotating angle from (0,0) to ...
expanding on the idea: imaginairy plane, fourier transform, hartley transform, digital signal processing, ....
last but not least: finding the angle where the capacitor changes from charging to discharging and the for the inductor: where
the magnetic flux is changing from building up to inducing a current (or @ which angles the current changes direction)
once you determine those angles THEN you write the integral equation (and solve your problem)