orthonormal basis, basis of subspace

ricta02

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Apr 29, 2019
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11937
 

ricta02

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Apr 29, 2019
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im completely stuck I know an orthogonal vector is one whose dot product is 0 but don't know how to go about this problem
 

tkhunny

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How do you prove "Perpendicular"?

Have you considered an "Orthoginalization" process?
 

ricta02

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a vector is perpendicular to another vector is 9a-9b-1c-d=0
the gram schmitd using only one vector gives me only one vector and its orthonormal I just need orthogonal
 

daon2

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Aug 17, 2011
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You want the basis of the nullspace of [9,-9,-1,-1]~[1,-1,-1/9,-1/9]. The nullspace is orthogonal to the row space.

The solution set is almost immediate:

\(\displaystyle \begin{pmatrix}x+y/9+z/9\\x\\y\\z\end{pmatrix} = x\begin{pmatrix}1\\1\\0\\0\end{pmatrix}+y\begin{pmatrix}1/9\\0\\1\\0\end{pmatrix}+z\begin{pmatrix}1/9\\0\\0\\1\end{pmatrix}\)

You can remove the fractions if desired by considering an appropriate multiple.
 
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