there are 4 straight lines in a plane so that no two lines are parallel and no three lines are concurrent determine the number of points of intersection .
I know what concurrent means that three lines or more cannot have a common intersection point.
Now before any approach I wanted to draw the Diagram.
Firstly, i draw the Diagram in such a way where every line was cutting every other except the last 4 th line which cut only two lines.
So the no of intersection points came 5 .
But answer is 6 .
Then I draw the Diagram where every line cuts each other then came 6 Intersection points.(4c2)
So why the question demands that every line should cut each other?
I know what concurrent means that three lines or more cannot have a common intersection point.
Now before any approach I wanted to draw the Diagram.
Firstly, i draw the Diagram in such a way where every line was cutting every other except the last 4 th line which cut only two lines.
So the no of intersection points came 5 .
But answer is 6 .
Then I draw the Diagram where every line cuts each other then came 6 Intersection points.(4c2)
So why the question demands that every line should cut each other?