two lines are perpindicular if their slopes are m2=- 1/[m1]
the equation of a line is y=mx+b, where m is the slope of the line
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A)
find the line that passes thru [0,5] and [-3,-4]
1) y=mx+b but y=5 when x=0
5=m0+b
b=5
2) y=mx+b but y=-4 when x=-3 and b=5
-4=m[-3]+5
-9=-3m
m=3
the equation of the line is y=3x+5
[ you can check this by seeing if the two points are on the line]
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B)
write the equation of any line perpindicular to the line y=3x+5
1) for a line to be perpindicular to y=3x+5 , it must have a slope of -1/3,or - 1 over the slope of the given line
y=mx+b where m=-1/3
y=[-1/3] x + b answer
hope this helps