#### getoutofmylaboratory

##### New member

- Joined
- Nov 10, 2013

- Messages
- 23

Without further ado:

Find an equation of a line through the given point and (a) parallel to and (b) perpendicular to the given line.

y = 3(x - 2) + 1 at (0, 3)

And my work:

a) y - y

_{1}= 3[(x - 2) - x

_{1}]

y - 3 = 3[(x - 2) - 0]

y - 3 = 3x - 6

**y = 3x - 3**

However, the online calculator I used to check the work says the answer is: y = 3x

**+**3

Not sure where I might have gone wrong or if the calculator was rubbish.

b) m = -1/3

y - y

_{1}= -1/3[(x - 2) - x

_{1}]

y - 3 = -1/3[(x - 2) - 0]

y - 3 = -1/3x + 2/3

**y = -1/3x + 3 2/3**

Again, I was somewhat close, but the online calculator came up with: y = -1/3x + 3

Thanks for any help, I'm really stressing out over this!