tryjac said:

Could I get some help with the following:

Write an equation of the line that goes through the point (5, 3) and is parallel to the line y = -2x + 2

You need to use the point-slope formula.

y - y1 = m(x - x1), where (x1, y1) represents the point you were given or point (5, 3).

Since the equation of the line we seek is parallel to the given equation in the question, then the slope must be the same. So, our slope is -2.

We now plug and chug.

y - 5 = -2(x - 3)

y - 5 = -2x + 6

We now isolate y.

y = -2x + 6 + 5

y = -2x + 11....This equation is parallel to the the equation given to you in the question.

How do I know it's parallel? The slope is -2 for BOTH equations.

That's it!