raidershero
New member
- Joined
- Oct 17, 2012
- Messages
- 6
I need help with this problem on my review sheet for Calc 1.
At how many values of 'x' is the function f(x) = (4x2-5x+1)(x-3) parallel to y=3x - 9?
What I've done is take the derivative of f(x) and I end up with:
f'(x) = 12x2 - 24x + 16
In order to solve this problem aren't I supposed to set this equal to the slope of y, which is 3?
If this is indeed the case then I would need to use the quadratic formula. Doing so, however, results in a negative number under the radical. What am I doing wrong? The answer key says the answer should be 2.
Thanks.
At how many values of 'x' is the function f(x) = (4x2-5x+1)(x-3) parallel to y=3x - 9?
What I've done is take the derivative of f(x) and I end up with:
f'(x) = 12x2 - 24x + 16
In order to solve this problem aren't I supposed to set this equal to the slope of y, which is 3?
If this is indeed the case then I would need to use the quadratic formula. Doing so, however, results in a negative number under the radical. What am I doing wrong? The answer key says the answer should be 2.
Thanks.