Not sure how to approach Q11i
M MathsQuestionAsker New member Joined May 6, 2022 Messages 1 May 6, 2022 #1 Not sure how to approach Q11i
BigBeachBanana Senior Member Joined Nov 19, 2021 Messages 2,182 May 6, 2022 #2 \(\displaystyle x=\tan(\theta)=\frac{\sin(\theta)}{\cos(\theta)}=\frac{\sin(\theta)}{y}\) Find the value of [imath]\sin(\theta)[/imath] in terms of y. Tip: Draw a triangle.
\(\displaystyle x=\tan(\theta)=\frac{\sin(\theta)}{\cos(\theta)}=\frac{\sin(\theta)}{y}\) Find the value of [imath]\sin(\theta)[/imath] in terms of y. Tip: Draw a triangle.
D Deleted member 4993 Guest May 6, 2022 #3 MathsQuestionAsker said: Not sure how to approach Q11i View attachment 32615 Click to expand... Another approach: sec2(Θ) - tan2(Θ) = 1
MathsQuestionAsker said: Not sure how to approach Q11i View attachment 32615 Click to expand... Another approach: sec2(Θ) - tan2(Θ) = 1