parametrizing a curve: x(t) = 2 - sin(t), y(t) = cos(t)

[klpierc2]

I can't seem to express this equation in x and y:

. . .x(t) = 2 - sin(t)

. . .y(t) = cos(t)

I tried x^2 + y^2, solving for t, but I'm just stuck--Any help please?! :lol:

 

[stapel]

I'm not sure what x² + y² would get you. Instead, try:

. . . . .x = 2 - sin(t)

. . . . .sin(t) = 2 - x

. . . . .sin² = 4 - 4x + x²

. . . . .y = cos(t)

. . . . .y² = cos²(t)

What identity holds for sin²(ß) + cos²(ß), regardless of the measure of the angle ß?

Eliz.