A asomma99 New member Joined Feb 18, 2014 Messages 4 Feb 18, 2014 #1 I need help with finding the partial derivative with respect to Psubx then again with Psuby. u/[(3/5(Psubx))^(3/5)(2/5(Psuby))^(2/5)]
I need help with finding the partial derivative with respect to Psubx then again with Psuby. u/[(3/5(Psubx))^(3/5)(2/5(Psuby))^(2/5)]
D Deleted member 4993 Guest Feb 18, 2014 #2 asomma99 said: I need help with finding the partial derivative with respect to Psubx then again with Psuby. u/[(3/5(Psubx))^(3/5)(2/5(Psuby))^(2/5)] Click to expand... As posted - problem does not make sense to me. Post exact problem AND: Please share your work with us . If you are stuck at the beginning tell us and we'll start with the definitions. You need to read the rules of this forum. Please read the post titled "Read before Posting" at the following URL: http://www.freemathhelp.com/forum/th...Before-Posting
asomma99 said: I need help with finding the partial derivative with respect to Psubx then again with Psuby. u/[(3/5(Psubx))^(3/5)(2/5(Psuby))^(2/5)] Click to expand... As posted - problem does not make sense to me. Post exact problem AND: Please share your work with us . If you are stuck at the beginning tell us and we'll start with the definitions. You need to read the rules of this forum. Please read the post titled "Read before Posting" at the following URL: http://www.freemathhelp.com/forum/th...Before-Posting
A asomma99 New member Joined Feb 18, 2014 Messages 4 Feb 18, 2014 #3 I'm stuck at the beginning The problem is U divided by [ ( 3/5(Psubx) to the (3/5) ) ( 2/5(Psuby)to the (2/5) ) ] Sent from my XT907 using Tapatalk
I'm stuck at the beginning The problem is U divided by [ ( 3/5(Psubx) to the (3/5) ) ( 2/5(Psuby)to the (2/5) ) ] Sent from my XT907 using Tapatalk
A asomma99 New member Joined Feb 18, 2014 Messages 4 Feb 18, 2014 #4 The Psubx is P subscript x Sent from my XT907 using Tapatalk
D Deleted member 4993 Guest Feb 18, 2014 #5 asomma99 said: The Psubx is P subscript x Sent from my XT907 using Tapatalk Click to expand... You already have Px and Py in your expression - I do not understand what is meant by find Px & Py from the given expression!!
asomma99 said: The Psubx is P subscript x Sent from my XT907 using Tapatalk Click to expand... You already have Px and Py in your expression - I do not understand what is meant by find Px & Py from the given expression!!
A asomma99 New member Joined Feb 18, 2014 Messages 4 Feb 18, 2014 #6 Its find the partial derivative with respect to PX. Sent from my XT907 using Tapatalk