C CatchThis2 Junior Member Joined Feb 6, 2010 Messages 96 Feb 24, 2011 #1 Find the partial derivative indicated. Assume the variables are restricted to a domain on which the function is defined.
Find the partial derivative indicated. Assume the variables are restricted to a domain on which the function is defined.
D Deleted member 4993 Guest Feb 24, 2011 #2 CatchThis2 said: Find the partial derivative indicated. Assume the variables are restricted to a domain on which the function is defined. Click to expand... Assume that "M" is the only independant variable. Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.
CatchThis2 said: Find the partial derivative indicated. Assume the variables are restricted to a domain on which the function is defined. Click to expand... Assume that "M" is the only independant variable. Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,325 Feb 24, 2011 #3 My first question would if r and G are independent of M? If so, \(\displaystyle \frac{\partial}{\partial M}\frac{4\pi r^\frac{7}{2}}{\sqrt{G\cdot M}} = \frac{\partial}{\partial M}\frac{4\pi r^\frac{7}{2}}{\sqrt{G}}\cdot \frac{1}{\sqrt{M}} = \frac{4\pi r^\frac{7}{2}}{\sqrt{G}}\cdot \frac{\partial}{\partial M}\frac{1}{\sqrt{M}}\)
My first question would if r and G are independent of M? If so, \(\displaystyle \frac{\partial}{\partial M}\frac{4\pi r^\frac{7}{2}}{\sqrt{G\cdot M}} = \frac{\partial}{\partial M}\frac{4\pi r^\frac{7}{2}}{\sqrt{G}}\cdot \frac{1}{\sqrt{M}} = \frac{4\pi r^\frac{7}{2}}{\sqrt{G}}\cdot \frac{\partial}{\partial M}\frac{1}{\sqrt{M}}\)