PEMDAS and BODMAS

[cleary.not.a.geek]

Can you please help settle and ongoing argument between members of a group i am in. There seem to be Two camps.: those who pick "b" and those who insist the answer is "c"
This problem may seem very elementary... But it brought up all kinds of references to PEMDA and BODMAS

View attachment 12945 Here were some
Ok...
All the "A's" are wrong
All the "D"'s are wrong
Its either "B" or "C" depending on whether you add or subtract at the end of the equation:
3-3×0+3÷3=
3-0+1...
(can we all agree on that?)
Doing Muliplication THEN Division,
yields 3×0=0 and 3÷3=1 bring us to
3-0+1...
OR if you prefer, the BODMAS way, DIVIDE first
3÷3=1 and. THEN MULTIPLY 3×0=0,
Again yielding 3-0+1
So far, so good, either way it's 3-0+1
But then there SEEM to be two approaches:
If you say 3-0=3, and 3+1=4
You'll get 4...BUT
If you say 0+1=1, and 3-1=2
You'll get 2
BUT...Don't BOTH PEMDAS and BODMAS
say "A.S." at the end of the acronym?
So, doing the "ADDITION" FIRST...0+1=1,
and THEN the SUBTRACTION,
YOU GET 3-1=2

so i would say the "2's"
(or, the "B's") have it.
Just sayin....- lol?
my thoughts:

 

[Dr.Peterson]

PEMDAS and BODMAS are not meant to be taken letter by letter; they are just summaries of the same basic rules:

• Parentheses/Brackets overrule anything else
• Exponents are applied first
• Multiplication and Division are done next, left to right
• Addition and Subtraction are done last, left to right

So in 3-3×0+3÷3 you first multiply and divide, 3-0+1, and then add and subtract (left to right): 3-0 = 3, 3+1 = 4.