#### susan pearson

##### New member

- Joined
- Aug 16, 2006

- Messages
- 9

. . .(2x<sup>2</sup> - 2x)/(x<sup>3</sup> - 4x<sup>2</sup> - x + 4) - (16)/(2x<sup>3</sup> - 6x<sup>2</sup> - 8x)

I realize I need to find the LCD (the Least Common Denominator) and, before doing this, I need to factor out my denominators. I came up with:

. . .[2x(x - 1)] / [(x<sup>2</sup> - 1)(x - 4)] . . .-. . . 4<sup>2</sup> / [2x(x - 4)(x + 1)]

But after this, I got lost.

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*Edited by stapel -- Reason for edit: clarifying formatting*