perim. 308'; length 34' more than 2X width; find dim. of rec

Garry

New member
Joined
Dec 31, 2008
Messages
2
The perimeter of a rectangular playground area is 308 feet. If the length of the playground is 34 feet more than twice the width, find the length and width of the playground. construct an algebraic equation with a variable and solve using
algebra steps. Stuck..Help
 

Denis

Senior Member
Joined
Feb 17, 2004
Messages
1,444
Re: Algebra

That's pretty basic stuff Garry: WHY are you stuck?

If width = w, then length = 2w + 34 : understand?
Carry on...
 

Jhonson9009

New member
Joined
Jan 13, 2009
Messages
2
Given that the perimeter of a rectangular playground area is 308 feet.
Let w be the width and l be the length of playground
also, given that the length of the playground is 34 feet more than twice the width.
Therefore
l = 34 + 2w
we know that, the perimeter of a rectangular playground = 2(l + w)
therefore by puting the values of l and w in above equation we will get the perimeter of the rectangular playground.
 
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