B becky123 New member Joined Mar 19, 2007 Messages 4 Mar 19, 2007 #1 I can't figure out this one: The perimeter of a rectangle is 160 ft. One fourth the length is the same as twice the width. Find the dimensions of the rectangle. thanks for the help
I can't figure out this one: The perimeter of a rectangle is 160 ft. One fourth the length is the same as twice the width. Find the dimensions of the rectangle. thanks for the help
J jwpaine Full Member Joined Mar 10, 2007 Messages 723 Mar 19, 2007 #2 You have length A and width B {2A + 2B = 160 {(1/4)A = 2B Solve the system of equations. Use Substitution. Start by substituting (1/4)A into 2B in the first equation... and then solve the linear equation for A ----> 2A + (1/4)A = 160 once you get the value of A... substitute that value into either equation and solve for B You will then be able to find your height and width.
You have length A and width B {2A + 2B = 160 {(1/4)A = 2B Solve the system of equations. Use Substitution. Start by substituting (1/4)A into 2B in the first equation... and then solve the linear equation for A ----> 2A + (1/4)A = 160 once you get the value of A... substitute that value into either equation and solve for B You will then be able to find your height and width.
