Perpendicular Vector

[markraz]

Hi, If I have a vector V = <i j k> and a plane in form of ax + by + cz + d = 0
is it possible to find a vector 90 degrees from vector V??

thanks

 

[pka]

Hi, If I have a vector V = <i j k> and a plane in form of ax + by + cz + d = 0
is it possible to find a vector \(\displaystyle \frac{\pi}{2}\) from vector V??

Any vector \(\displaystyle <p,q,r>\) having the property that \(\displaystyle <p,q,r>\cdot<i,j,k>=0\) is perpendicular to \(\displaystyle <i,j,k>\).

 

[Dr.Peterson]

Assuming you mean a vector in the given plane that is orthogonal to V, you could make use of either a plane normal to V, or the vector normal to the plane. Do you see how?

 

[markraz]

thanks guys, I actually remember this from my books now that you reminded me