for a 3.8" OD 90 degree pipe bend, how do you calculate the the amount the outside/outer edge of a pipe exceeds the inside/inner outer edge? My answers come out to be 50% of the "correct" anwer when I tried--
(assuming pipe's cross-sectional (OD) = 3.8", 1/4 x pi x D:
.25 x 3.1417 x 3.8" = 2.985"
(correct answer = 5.969). I would have thought a 90 degree bend required dividing by 4; a 180 degree bend, dividing by 2, etc.
(assuming pipe's cross-sectional (OD) = 3.8", 1/4 x pi x D:
.25 x 3.1417 x 3.8" = 2.985"
(correct answer = 5.969). I would have thought a 90 degree bend required dividing by 4; a 180 degree bend, dividing by 2, etc.