Physicsrapper
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- Aug 16, 2014
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The earth's radius R is 6370 km. Find the height of the water, if 10 000 km^3 of water would have flooded a disc shaped earth.
If a disc-shaped world would be covered with water, wouldn't it be a cylinder then?
So, the cylinde formulas:
Volume: π*r^2*h
Surface area: π*r^2
Surface area of the earth: π * 6370^2 = 127476090.9
Volume / Surface area = hight
10 000 = 127476090.9 * h
10 000 / 127476090.9 = h
h = 7.8 cm
In the solution it should be 5.9 cm. What did I wrong?
If a disc-shaped world would be covered with water, wouldn't it be a cylinder then?
So, the cylinde formulas:
Volume: π*r^2*h
Surface area: π*r^2
Surface area of the earth: π * 6370^2 = 127476090.9
Volume / Surface area = hight
10 000 = 127476090.9 * h
10 000 / 127476090.9 = h
h = 7.8 cm
In the solution it should be 5.9 cm. What did I wrong?