Conditional Probability
Drawing a 5-card hand from a standard deck of 52 cards: Let X be a random variable representing the number of different suits in your hand. Let K be the random variable representing how many kings are in your hand. Given that there is one king, find the conditional probability mass function of X.
For example, Pr{X = 2 | K=1} = Pr{ X=2 and K=1}/Pr{K=1} This must be done for X=1, X=2, X=3, and X=4. I have calculated Pr{K=1} as (4C1)(48C4)/(52C5), but am having trouble with the joint probability of kings and suits.
Please help, due tomorrow!!!
Drawing a 5-card hand from a standard deck of 52 cards: Let X be a random variable representing the number of different suits in your hand. Let K be the random variable representing how many kings are in your hand. Given that there is one king, find the conditional probability mass function of X.
For example, Pr{X = 2 | K=1} = Pr{ X=2 and K=1}/Pr{K=1} This must be done for X=1, X=2, X=3, and X=4. I have calculated Pr{K=1} as (4C1)(48C4)/(52C5), but am having trouble with the joint probability of kings and suits.
Please help, due tomorrow!!!
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