Please help lol this is the last question on my assessment and I genuinely can't solve it I have been trying for like 20 minutes

hotsaucehead

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Determine the equation of a line perpendicular to 4x + 3y - 6 = 0 with the same y-intercept as the line 2x = 4y + -8
 
Determine the equation of a line perpendicular to 4x + 3y - 6 = 0 with the same y-intercept as the line 2x = 4y + -8
What is the slope of the line describ ed by:

4x + 3y + 6 = 0....?​

what will be the slope of the line perpendicular to it?
 
There are three main things you need to do in order to solve this.

First, you need to find the slope of the line perpendicular to 4x + 3y -6 = 0. I would rewrite this in slope-intercept form to get y=-4/3 x + 2. Since the slope of this line is -4/3, the slope of the line perpendicular to that would be 3/4, since it's the negative reciprocal.

Second, you need to find the y-intercept of the line 2x = 4y + -8. Again, I would rewrite it in slope-intercept form to get y=1/2 x + 2. The y-intercept of this line is 2.

Third, take the information we just found in the first two steps to write your answer. You have everything you need to write it in slope-intercept form now.
 
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