C cowboys13 New member Joined Oct 1, 2006 Messages 1 Oct 1, 2006 #1 An 18-foot wire is to be cut so that the longer piece is 5 times longer than the shorter piece. Find the length of each piece.
An 18-foot wire is to be cut so that the longer piece is 5 times longer than the shorter piece. Find the length of each piece.
J jonboy Full Member Joined Jun 8, 2006 Messages 547 Oct 1, 2006 #2 Re: please help with this problem Hello, Cowboys! cowboys13 said: an 18-foot wire is to be cut so that the longer piece is 5 times longer than the shorter piece. find the length of each piece. Click to expand... The shorter side is:\(\displaystyle \L \;x\) The longer side is:\(\displaystyle \L \;5x\) Since both total to 18 ft:\(\displaystyle \L \;5x\,+\,x\,=\,18\) \(\displaystyle \L \;6x\,=\,18\) \(\displaystyle \L \;x\,=\,3\) So fill this \(\displaystyle x\) value back in to get your lengths of the wire.
Re: please help with this problem Hello, Cowboys! cowboys13 said: an 18-foot wire is to be cut so that the longer piece is 5 times longer than the shorter piece. find the length of each piece. Click to expand... The shorter side is:\(\displaystyle \L \;x\) The longer side is:\(\displaystyle \L \;5x\) Since both total to 18 ft:\(\displaystyle \L \;5x\,+\,x\,=\,18\) \(\displaystyle \L \;6x\,=\,18\) \(\displaystyle \L \;x\,=\,3\) So fill this \(\displaystyle x\) value back in to get your lengths of the wire.
