1) Hint: The probabilities of all the different events (in this case, two, being "yes" or "no") have to add up to "1" (for "100% of all the possibilities").

2) Make a six-by-six grid. Along the left-hand side, label from top to bottom from "1" to "6". Along the top, label from left to right from "1" to "6". Then fill each square in the grid with the sum of the numbers from the top of the grid and the side of the grid. For instance, the second square in the third row will have a "2" up top and a "3" to the left, so the sum would be "5".

Obviously, there are thirty-six possible outcomes. How many of those thirty-six are "2" or more?

3) Use a grid like that above.

a) Leave the grid's squares empty of numbers. Just shade in those squares that have a "5" for one or both of the labels. Count up the shaded squares, and divide by "36".

b) Leave the grid's squares empty of numbers. Just shade in those squares that aren't in the second row or second column. Count up the shaded squares, and divide by "36".

c) Leave the grid's squares empty of numbers. Note that, on the one diagonal, you have pairs with the same values for each die. Shade in the other squares.

d) Shade in only those squares on the first row and first column, except for one of the squares (that corresponds to both of the die having a "1" showing).

Eliz.