No. The marked 100 degree angle AOD is not an **inscribed **angle, but a **central **angle; so arc AD has measure 100 degrees.

I would mark the other three central angles (at O) and use those to find the arcs in the same way.

Then I would find the inscribed angles, such as DAC.

Then angle AED is different; you might think about quadrilateral AEDO. What are the angles at A and D? Or you might have a theorem you can apply directly.

the arc will have the same measure as a central angle? does that mean all the angles in the center have the same measurement as arcs?

I think

angle BOC will be 100,

angle AOB will be 80

angle DOC will be 80?

does it make the arcs across from it the same?

The inscribed angle DAC will be 40 since arc DC is 80.

quadrilateral had to equal 360,

and angle A and D are congruent

angle A and D are 40?

40+40+100+180 = 360

angle AED = 180?

arc AD = 100

arc DC = 80

arc AB = 80

angle DAC = 40

arc ACD = 260

angle ACB = 40

angle AED = 180

arc ADC = 180