Pls help me :((

the loop is in the interval [MATH]-\frac{3}{2} \le x \le 0[/MATH]
using symmetry …

[MATH]S = 2 \int_{-\frac{3}{2}}^0 \sqrt{1+[f’(x)]^2} \, dx[/MATH]
where [MATH]f(x) = \dfrac{\sqrt{x^2(2x+3)}}{3}[/MATH]
 
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