Please review your original problem and make sure you posted correct numbers.A prize of $720.00 was divided between three friends. Martin and Daniel respectively received 1/4 and 3/5 of the amount that Joseph received. What was the amount that Joseph received?
yeah, tbh i've already finished itHello, and welcome to FMH!
I would use a bit of algebra to solve this problem. Suppose we let \(J\) be the amount Joseph received. And then:
\(\displaystyle M=\frac{1}{4}J\) is the amount Martin received
\(\displaystyle D=\frac{3}{5}J\) is the amount Daniel received
Now, we know the sum of the amounts recieved is the total prize (in dollars)
\(\displaystyle M+D+J=720\)
\(\displaystyle \frac{1}{4}J+\frac{3}{5}J+J=720\)
Can you finish?
yeah the question is not wellmadePlease review your original problem and make sure you posted correct numbers.
The numbers are not coming out "nice". These problems generally have nice numbers - specially if these are to be solved "without" algebra.