Plz can any one help me to plot this equation

[nouredinne]

i want to plot θ against β

Sin(θ-β)-2sin(2(θ-β))-sin(2θ)=0

0°<​θ<90°

0°<β<90°

 

[stapel]

i want to plot θ against β

What does this mean? Are you trying to solve the equation for the one variable in terms of the other?

Sin(θ-β)-2sin(2(θ-β))-sin(2θ)=0

0°<​θ<90°

0°<β<90°

What are your thoughts? What have you tried? How far have you gotten? Where are you stuck?

Please be complete. Thank you!

 

[Deleted member 4993]

i want to plot θ against β

Sin(θ-β)-2sin(2(θ-β))-sin(2θ)=0

0°<​θ<90°

0°<β<90°

use sin(2x) = 2sin(x)cos(x) and sin(x-y) = sin(x)cos(y) - sin(y)cos(x)

What are your thoughts?

Please share your work with us ...even if you know it is wrong

If you are stuck at the beginning tell us and we'll start with the definitions.

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