point of inflection of piecewise function g(x) over (-5, 4)

Re: pont of inflection

What are you having trouble with? Here are some hints that may help:
If g(t) represents the integral of f(t) for that particular interval, you can think of f(t) as the derivative of g(t) and f'(t) = g"(t).
What conditions must you have in order for a point on g to be an inflection point?

Now, WHERE would you suspect to find an inflection point given f(t) = g'(t) (for that particular interval)?

Any input from you would be great.
 
Re: pont of inflection

im on math team and it was a question on a team test of ours. i dont have a lot of calculus under my belt. i know derivates. but what is point of inflection
 
Re: pont of inflection

Math wiz ya rite 09 said:
im on math team and it was a question on a team test of ours. i dont have a lot of calculus under my belt. i know derivates. but what is point of inflection
Click to expand...

A point on a curve at which the derivative changes sign: \(\displaystyle \frac{D^2f}{Dx} = 0\)

(think of the tangent changing from a negative slope to a positive slope)
 
How does your book (or this text) define inflection points? Must the second derivative equal zero, or can it be undefined? Or should you only look at points where the second derivative changes sign?

Thank you! :D

Eliz.
 
So where is g"(t) = f'(t) = 0? But be careful when using this, just knowing that f"(t) = 0 is not sufficient in determining whether or not it actually is an inflection point (ex. y = x[sup:147sei12]4[/sup:147sei12] it is concave up everywhere)
 
So what x values can you have so that g(t) will have that inflection point given f(t)?
 
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